Kinematics Question 410

Question: A ball is released from the top of tower of height h meter. It takes T second to reach the ground. What is the position in (m) from the ground of the ball in T/3 second?

Options:

A) h9

B) 7h9

C) 8h9

D) 17h18

Show Answer

Answer:

Correct Answer: C

Solution:

In T3 sec, the distance travelled = 12g(T3)2=h9

Position of the ball from the ground = hh9=8h9m



NCERT Chapter Video Solution

Dual Pane