Kinematics Question 410
Question: A ball is released from the top of tower of height h meter. It takes T second to reach the ground. What is the position in (m) from the ground of the ball in T/3 second?
Options:
A) $ \frac{h}{9} $
B) $ \frac{7h}{9} $
C) $ \frac{8h}{9} $
D) $ \frac{17h}{18} $
Show Answer
Answer:
Correct Answer: C
Solution:
In $ \frac{T}{3} $ sec, the distance travelled = $ \frac{1}{2}g{{( \frac{T}{3} )}^{2}}\text{=}\frac{h}{9} $
$ \therefore $ Position of the ball from the ground = $ h-\frac{h}{9}=\frac{8h}{9}m $
