Kinematics Question 390
Question: Two particles P and Q simultaneously start moving from point A with velocities 15 m/s and 20 m/s respectively. The two particles move with acceleration equal in magnitude but opposite in direction. When P overtakes Q at B then it’s velocity is 30 m/s The velocity of Q at point B will be
Options:
A) 30 m/s
B) 5 m/s
C) 20 m/s
D) 15 m/s
Show Answer
Answer:
Correct Answer: B
Solution:
As magnitude of acceleration is same $ \frac{30-15}{t}=\frac{20-{{V} _{Q}}}{t} $
$ 15=20-{{V} _{Q}}\Rightarrow 5\text{ m/s} $
