Kinematics Question 390

Question: Two particles P and Q simultaneously start moving from point A with velocities 15 m/s and 20 m/s respectively. The two particles move with acceleration equal in magnitude but opposite in direction. When P overtakes Q at B then it’s velocity is 30 m/s The velocity of Q at point B will be

Options:

A) 30 m/s

B) 5 m/s

C) 20 m/s

D) 15 m/s

Show Answer

Answer:

Correct Answer: B

Solution:

As magnitude of acceleration is same $ \frac{30-15}{t}=\frac{20-{{V} _{Q}}}{t} $

$ 15=20-{{V} _{Q}}\Rightarrow 5\text{ m/s} $



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