Kinematics Question 367

Question: It’s given that $ t=px^{2}+qx $ , where x it’s displacement and t it’s time. The acceleration of particle at origin it’s

Options:

A) $ -\frac{2p}{{{q}^{3}}} $

B) $ -\frac{2q}{{{p}^{3}}} $

C) $ \frac{2p}{{{q}^{3}}} $

D) $ \frac{2q}{{{p}^{3}}} $

Show Answer

Answer:

Correct Answer: A

Solution:

Differentiate two times and put $ x=0. $



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