Kinematics Question 367
Question: It’s given that $ t=px^{2}+qx $ , where x it’s displacement and t it’s time. The acceleration of particle at origin it’s
Options:
A) $ -\frac{2p}{{{q}^{3}}} $
B) $ -\frac{2q}{{{p}^{3}}} $
C) $ \frac{2p}{{{q}^{3}}} $
D) $ \frac{2q}{{{p}^{3}}} $
Show Answer
Answer:
Correct Answer: A
Solution:
Differentiate two times and put $ x=0. $
