Kinematics Question 29
Question: A person goes 10 km north and 20 km east. What will be displacement from initial point [AFMC 1994, 2003]
Options:
A) 22.36 km
B) 2 km
C) 5 km
D) 20 km
Correct Answer: A $ \overrightarrow{AC}=\overrightarrow{AB}+\overrightarrow{BC} $ $ AC=\sqrt{{{(AB)}^{2}}+{{(BC)}^{2}}} $ $ =\sqrt{{{(10)}^{2}}+{{(20)}^{2}}} $ $ =\sqrt{100+400} $ $ =\sqrt{500} $ $ =22.36km $
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