Kinematics Question 29

Question: A person goes 10 km north and 20 km east. What will be displacement from initial point [AFMC 1994, 2003]

Options:

A) 22.36 km

B) 2 km

C) 5 km

D) 20 km

Show Answer

Answer:

Correct Answer: A

Solution:

$ \overrightarrow{AC}=\overrightarrow{AB}+\overrightarrow{BC} $

$ AC=\sqrt{{{(AB)}^{2}}+{{(BC)}^{2}}} $

$ =\sqrt{{{(10)}^{2}}+{{(20)}^{2}}} $

$ =\sqrt{100+400} $

$ =\sqrt{500} $

$ =22.36km $



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