Kinematics Question 29

Question: A person goes 10 km north and 20 km east. What will be displacement from initial point [AFMC 1994, 2003]

Options:

A) 22.36 km

B) 2 km

C) 5 km

D) 20 km

Show Answer

Answer:

Correct Answer: A

Solution:

AC=AB+BC

AC=(AB)2+(BC)2

=(10)2+(20)2

=100+400

=500

=22.36km



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक