Kinematics Question 27
Question: The magnitudes of vectors $ \vec{A},\vec{B} $ and $ \vec{C} $ are 3, 4 and 5 unit respectively. If $ \vec{A}+\vec{B}=\vec{C} $ , the angle between $ \vec{A} $ and $ \vec{B} $ it’s [CBSE PMT 1990]
Options:
A) $ \frac{\pi }{2} $
B) $ {{\cos }^{-1}}(0.6) $
C) $ {{\tan }^{-1}}( \frac{7}{5} ) $
D) $ \frac{\pi }{4} $
Correct Answer: A $ C=\sqrt{A^{2}+B^{2}} $ = $ \sqrt{3^{2}+4^{2}}=5 $
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Answer:
Solution:
$ \therefore $ Angle between $ \overrightarrow{A} $ and $ \overrightarrow{B} $ is $ \frac{\pi }{2} $
