Kinematics Question 27

Question: The magnitudes of vectors $ \vec{A},\vec{B} $ and $ \vec{C} $ are 3, 4 and 5 unit respectively. If $ \vec{A}+\vec{B}=\vec{C} $ , the angle between $ \vec{A} $ and $ \vec{B} $ it’s [CBSE PMT 1990]

Options:

A) $ \frac{\pi }{2} $

B) $ {{\cos }^{-1}}(0.6) $

C) $ {{\tan }^{-1}}( \frac{7}{5} ) $

D) $ \frac{\pi }{4} $

Show Answer

Answer:

Correct Answer: A

Solution:

$ C=\sqrt{A^{2}+B^{2}} $ = $ \sqrt{3^{2}+4^{2}}=5 $
$ \therefore $ Angle between $ \overrightarrow{A} $ and $ \overrightarrow{B} $ is $ \frac{\pi }{2} $



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