Kinematics Question 269
Question: The angle between the vectors $ (\hat{i}+\hat{j}) $ and $ (\hat{j}+\hat{k}) $ it’s [EAMCET 1995]
Options:
A) 30°
B) 45°
C) 60°
D) 90°
Correct Answer: C $ (\hat{i}+\hat{j}).(\hat{j}+\hat{k})=0+0+1+0=1 $ $ \cos \theta =\frac{\vec{A}.\vec{B}}{|\vec{A}||\vec{B}|}=\frac{1}{\sqrt{2}\times \sqrt{2}}=\frac{1}{2} $ \ $ \theta =60{}^\circ $
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