Kinematics Question 269

Question: The angle between the vectors $ (\hat{i}+\hat{j}) $ and $ (\hat{j}+\hat{k}) $ it’s [EAMCET 1995]

Options:

A) 30°

B) 45°

C) 60°

D) 90°

Show Answer

Answer:

Correct Answer: C

Solution:

$ (\hat{i}+\hat{j}).(\hat{j}+\hat{k})=0+0+1+0=1 $

$ \cos \theta =\frac{\vec{A}.\vec{B}}{|\vec{A}||\vec{B}|}=\frac{1}{\sqrt{2}\times \sqrt{2}}=\frac{1}{2} $ \ $ \theta =60{}^\circ $



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