Kinematics Question 255
Question: A particle moves from position $ 3\hat{i}+2\hat{j}-6\hat{k} $ to $ 14\hat{i}+13\hat{j}+9\hat{k} $ due to a uniform force of $ (4\hat{i}+\hat{j}+3\hat{k})N. $ If the displacement in meters then work done will be [CMEET 1995; Pb. PMT 2002, 03]
Options:
A) 100 J
B) 200 J
C) 300 J
D) 250 J
Correct Answer: A $ S=\overrightarrow{r_2}-\overrightarrow{r_1} $ $ W=\overrightarrow{F}.\overrightarrow{S} $ $ =(4\hat{i}+\hat{j}+3\hat{k}).(11\hat{i}+11\hat{j}+15\hat{k}) $ $ =(4\times 11+1\times 11+3\times 15)=100J. $
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