Kinematics Question 201

Question: A ball is thrown vertically upwards from the top of a tower at $ 4.9m{{s}^{-1}} $ . It strikes the pond near the base of the tower after 3 seconds. The height of the tower it’s [Manipal MEE 1995]

Options:

A) 73.5 m

B) 44.1 m

C) 29.4 m

D) None of these

Show Answer

Answer:

Correct Answer: C

Solution:

$ h=ut+\frac{1}{2}gt^{2},\ t=3\ \sec ,\ u=-4.9\ m/s $
$ \Rightarrow h=-4.9\times 3+4.9\times 9=29.4\ m $



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