Kinematics Question 201
Question: A ball is thrown vertically upwards from the top of a tower at $ 4.9m{{s}^{-1}} $ . It strikes the pond near the base of the tower after 3 seconds. The height of the tower it’s [Manipal MEE 1995]
Options:
A) 73.5 m
B) 44.1 m
C) 29.4 m
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
$ h=ut+\frac{1}{2}gt^{2},\ t=3\ \sec ,\ u=-4.9\ m/s $
$ \Rightarrow h=-4.9\times 3+4.9\times 9=29.4\ m $
