Kinematics Question 17

Question: The sum of two forces acting at a point is 16 N. If the resultant force is 8 N and it’s direction is perpendicular to minimum force then the forces are [CPMT 1997]

Options:

A) 6 N and 10 N

B) 8 N and 8 N

C) 4 N and 12 N

D) 2 N and 14 N

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Answer:

Correct Answer: A

Solution:

$ A+B=16 $ (given) -(i)

$ \tan \alpha =\frac{B\sin \theta }{A+B\cos \theta }=\tan 90{}^\circ $

$ A+B\cos \theta =0 $

therefore $ \cos \theta =\frac{-A}{B} $ -(ii)

$ 8=\sqrt{A^{2}+B^{2}+2AB\cos \theta } $ -(iii)

By solving eq. (i), (ii) and (iii) we get $ A=6N, $

$ B=10N $



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