Kinematics Question 17
Question: The sum of two forces acting at a point is 16 N. If the resultant force is 8 N and it’s direction is perpendicular to minimum force then the forces are [CPMT 1997]
Options:
A) 6 N and 10 N
B) 8 N and 8 N
C) 4 N and 12 N
D) 2 N and 14 N
Correct Answer: A $ A+B=16 $ (given) -(i) $ \tan \alpha =\frac{B\sin \theta }{A+B\cos \theta }=\tan 90{}^\circ $ $ A+B\cos \theta =0 $ therefore $ \cos \theta =\frac{-A}{B} $ -(ii) $ 8=\sqrt{A^{2}+B^{2}+2AB\cos \theta } $ -(iii) By solving eq. (i), (ii) and (iii) we get $ A=6N, $ $ B=10N $
Show Answer
Answer:
Solution:
