Gravitation Question 60

Question: The depth at which the effective value of acceleration due to gravity is $ [\frac{g}{4}] $ is[MP PET 2003]

Options:

A) R

B) $ [\frac{3R}{4}] $

C) $ [11.2\times 10^{2}km{{s}^{-1}}] $

D) $ [\frac{R}{4}] $

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Answer:

Correct Answer: B

Solution:

$ [g’=g\left( 1-\frac{d}{R} \right)\Rightarrow \frac{g}{4}=g\left( 1-\frac{d}{R} \right)\Rightarrow d=\frac{3}{4}R] $



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