Gravitation Question 60
Question: The depth at which the effective value of acceleration due to gravity is $ [\frac{g}{4}] $ is[MP PET 2003]
Options:
A) R
B) $ [\frac{3R}{4}] $
C) $ [11.2\times 10^{2}km{{s}^{-1}}] $
D) $ [\frac{R}{4}] $
Show Answer
Answer:
Correct Answer: B
Solution:
$ [g’=g\left( 1-\frac{d}{R} \right)\Rightarrow \frac{g}{4}=g\left( 1-\frac{d}{R} \right)\Rightarrow d=\frac{3}{4}R] $
