Gravitation Question 53
Question: The acceleration due to gravity near the surface of a planet of radius R and density d is proportional to [MP PET 2002; AIEEE 2004]
Options:
A) $ [\frac{d}{R^{2}}] $
B) $ [dR^{2}] $
C) dR
D) $ [\frac{d}{R}] $
Show Answer
Answer:
Correct Answer: C
Solution:
$ [g=\frac{4}{3}\pi \rho GR\Rightarrow g\propto dR] $ $ [(\rho =d\ \text{given in the problem)}] $
