Gravitation Question 53

Question: The acceleration due to gravity near the surface of a planet of radius R and density d is proportional to [MP PET 2002; AIEEE 2004]

Options:

A) $ [\frac{d}{R^{2}}] $

B) $ [dR^{2}] $

C) dR

D) $ [\frac{d}{R}] $

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Answer:

Correct Answer: C

Solution:

$ [g=\frac{4}{3}\pi \rho GR\Rightarrow g\propto dR] $ $ [(\rho =d\ \text{given in the problem)}] $



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