Gravitation Question 52
Question: What will be the acceleration due to gravity at height h if h » R. Where R is radius of earth and g is acceleration due to gravity on the surface of earth[RPET 2001]
Options:
A) $ [\frac{g}{{{\left( 1+\frac{h}{R} \right)}^{2}}}] $
B) $ [g\left( 1-\frac{2h}{R} \right)] $
C) $ [\frac{g}{{{\left( 1-\frac{h}{R} \right)}^{2}}}] $
D) $ [g\left( 1-\frac{h}{R} \right)] $
Show Answer
Answer:
Correct Answer: A
Solution:
$ [{g}’=g{{\left( \frac{R}{R+h} \right)}^{2}}=\frac{g}{{{\left( 1+\frac{h}{R} \right)}^{2}}}] $
