Gravitation Question 52

Question: What will be the acceleration due to gravity at height h if h » R. Where R is radius of earth and g is acceleration due to gravity on the surface of earth[RPET 2001]

Options:

A) $ [\frac{g}{{{\left( 1+\frac{h}{R} \right)}^{2}}}] $

B) $ [g\left( 1-\frac{2h}{R} \right)] $

C) $ [\frac{g}{{{\left( 1-\frac{h}{R} \right)}^{2}}}] $

D) $ [g\left( 1-\frac{h}{R} \right)] $

Show Answer

Answer:

Correct Answer: A

Solution:

$ [{g}’=g{{\left( \frac{R}{R+h} \right)}^{2}}=\frac{g}{{{\left( 1+\frac{h}{R} \right)}^{2}}}] $



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