Gravitation Question 39
Question: Acceleration due to gravity is ?g? on the surface of the earth. The value of acceleration due to gravity at a height of 32 km above earth’s surface is (Radius of the earth = 6400 km)[KCET (Engg./Med.) 1999]
Options:
A) 0.9 g
B) 0.99 g
C) 0.8 g
D) 1.01 g
Show Answer
Answer:
Correct Answer: B
Solution:
$ [h=32,km] $ , $ [R=6400,km] $ ,
so $ [h«R] $
$ [{g}’=g\left( 1-\frac{2h}{R} \right)] $
$ [=g\left( 1-\frac{2\times 32}{6400} \right)] $
Þ $ [{g}’=\frac{99}{100}g=0.99,g] $
