Gravitation Question 39

Question: Acceleration due to gravity is ?g? on the surface of the earth. The value of acceleration due to gravity at a height of 32 km above earth’s surface is (Radius of the earth = 6400 km)[KCET (Engg./Med.) 1999]

Options:

A) 0.9 g

B) 0.99 g

C) 0.8 g

D) 1.01 g

Show Answer

Answer:

Correct Answer: B

Solution:

$ [h=32,km] $ , $ [R=6400,km] $ ,

so $ [h«R] $

$ [{g}’=g\left( 1-\frac{2h}{R} \right)] $

$ [=g\left( 1-\frac{2\times 32}{6400} \right)] $

Þ $ [{g}’=\frac{99}{100}g=0.99,g] $



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