Gravitation Question 312
Question: Two bodies of masses 4 kg and 9 kg are separated by a distance of 60 cm. A 1 kg mass is placed in between these two masses. If the net force on 1 kg is zero, then its distance from 4 kg mass is
Options:
A) 26 cm
B) 30 cm
C) 28 cm
D) 24 cm
Show Answer
Answer:
Correct Answer: D
Solution:
- $ [\therefore G\frac{4\times 1}{x^{2}}=G\frac{9\times 1}{{{\left( 60-x \right)}^{2}}}] $ $ [or,,\frac{2}{3}=\frac{x}{\left( 60-x \right)}\Rightarrow x=24,,cm] $
