Gravitation Question 312

Question: Two bodies of masses 4 kg and 9 kg are separated by a distance of 60 cm. A 1 kg mass is placed in between these two masses. If the net force on 1 kg is zero, then its distance from 4 kg mass is

Options:

A) 26 cm

B) 30 cm

C) 28 cm

D) 24 cm

Show Answer

Answer:

Correct Answer: D

Solution:

  • $ [\therefore G\frac{4\times 1}{x^{2}}=G\frac{9\times 1}{{{\left( 60-x \right)}^{2}}}] $ $ [or,,\frac{2}{3}=\frac{x}{\left( 60-x \right)}\Rightarrow x=24,,cm] $


जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक