Gravitation Question 264
Question: If the gravitational force between two objects were proportional to 1/R (and not as $ [1/R^{2})] $ where R is separation between them, then a particle in circular orbit under such a force would have its orbital speed v proportional to [CBSE PMT 1994; JIPMER 2001, 02]
Options:
A) $ [1/R^{2}] $
B) $ [R^{0}] $
C) $ [R^{1}] $
D) 1/R
Show Answer
Answer:
Correct Answer: B
Solution:
Gravitational force provides the required centripetal force for orbiting the satellite
$ [\frac{mv^{2}}{R}=\frac{K}{R}] $
because $ [\left( F\propto \frac{1}{R} \right)] $ \ $ [v\propto R{}^\circ ] $
