Gravitation Question 264

Question: If the gravitational force between two objects were proportional to 1/R (and not as [1/R2)] where R is separation between them, then a particle in circular orbit under such a force would have its orbital speed v proportional to [CBSE PMT 1994; JIPMER 2001, 02]

Options:

A) [1/R2]

B) [R0]

C) [R1]

D) 1/R

Show Answer

Answer:

Correct Answer: B

Solution:

Gravitational force provides the required centripetal force for orbiting the satellite

[mv2R=KR]

because [(F1R)] \ [vR]



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