Gravitation Question 264

Question: If the gravitational force between two objects were proportional to 1/R (and not as $ [1/R^{2})] $ where R is separation between them, then a particle in circular orbit under such a force would have its orbital speed v proportional to [CBSE PMT 1994; JIPMER 2001, 02]

Options:

A) $ [1/R^{2}] $

B) $ [R^{0}] $

C) $ [R^{1}] $

D) 1/R

Show Answer

Answer:

Correct Answer: B

Solution:

Gravitational force provides the required centripetal force for orbiting the satellite

$ [\frac{mv^{2}}{R}=\frac{K}{R}] $

because $ [\left( F\propto \frac{1}{R} \right)] $ \ $ [v\propto R{}^\circ ] $



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