Gravitation Question 233
Question: An earth satellite of mass m revolves in a circular orbit at a height h from the surface of the earth. R is the radius of the earth and g is acceleration due to gravity at the surface of the earth. The velocity of the satellite in the orbit is given by [NCERT 1983; AIEEE 2004]
Options:
A) $ [\frac{gR^{2}}{R+h}] $
B) Gr
C) $ [\frac{gR}{R+h}] $
D) $ [\sqrt{\frac{gR^{2}}{R+h}}] $
Show Answer
Answer:
Correct Answer: D
Solution:
$ [v_{0}=\sqrt{\frac{GM}{r}}=\sqrt{\frac{gR^{2}}{R+h}}] $
