Gravitation Question 233

Question: An earth satellite of mass m revolves in a circular orbit at a height h from the surface of the earth. R is the radius of the earth and g is acceleration due to gravity at the surface of the earth. The velocity of the satellite in the orbit is given by [NCERT 1983; AIEEE 2004]

Options:

A) $ [\frac{gR^{2}}{R+h}] $

B) Gr

C) $ [\frac{gR}{R+h}] $

D) $ [\sqrt{\frac{gR^{2}}{R+h}}] $

Show Answer

Answer:

Correct Answer: D

Solution:

$ [v_{0}=\sqrt{\frac{GM}{r}}=\sqrt{\frac{gR^{2}}{R+h}}] $



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