Gravitation Question 207
Question: The eccentricity of earth’s orbit is 0.0167. The ratio of its maximum speed in its orbit to its minimum speed is[NCERT 1973]
Options:
A) 2.507
B) 1.033
C) 8.324
D) 1.000
Show Answer
Answer:
Correct Answer: B
Solution:
$ [\frac{{v_{\max }}}{{v_{\min }}}=\frac{1+e}{1-e}=\frac{1+0.0167}{1-0.0167}=1.033] $
