Gravitation Question 207

Question: The eccentricity of earth’s orbit is 0.0167. The ratio of its maximum speed in its orbit to its minimum speed is[NCERT 1973]

Options:

A) 2.507

B) 1.033

C) 8.324

D) 1.000

Show Answer

Answer:

Correct Answer: B

Solution:

$ [\frac{{v_{\max }}}{{v_{\min }}}=\frac{1+e}{1-e}=\frac{1+0.0167}{1-0.0167}=1.033] $



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