Gravitation Question 152

Question:The escape velocity of a body on the surface of the earth is 11.2 km/s. If the earth’s mass increases to twice its present value and the radius of the earth becomes half, the escape velocity would become [CBSE PMT 1997]

Options:

A) 5.6 km/s

B) 11.2 km/s (remain unchanged)

C) 22.4 km/s

D) 44.8 km/s

Show Answer

Answer:

Correct Answer: C

Solution:

$ [v_{e}=\sqrt{\frac{2GM}{R}}] $

$ [v_{e}\propto \sqrt{\frac{M}{R}}] $

If M becomes double and R becomes half then escape velocity becomes two times.



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