Gravitation Question 152
Question:The escape velocity of a body on the surface of the earth is 11.2 km/s. If the earth’s mass increases to twice its present value and the radius of the earth becomes half, the escape velocity would become [CBSE PMT 1997]
Options:
A) 5.6 km/s
B) 11.2 km/s (remain unchanged)
C) 22.4 km/s
D) 44.8 km/s
Show Answer
Answer:
Correct Answer: C
Solution:
$ [v_{e}=\sqrt{\frac{2GM}{R}}] $
$ [v_{e}\propto \sqrt{\frac{M}{R}}] $
If M becomes double and R becomes half then escape velocity becomes two times.
