Electrostatics Question 793
Question: A ball of mass 1 g carrying a change $ {{10}^{-8}}C $ moves from a point A at potential 600 V to a point B at zero potential. The change in its K.E.
Options:
A) $ -6\times {{10}^{-6}}erg $
B) $ -6\times {{10}^{-6}}J $
C) $ 6\times {{10}^{-6}}J $
D) $ 6\times {{10}^{-6}}erg $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] As work is done by the field, K.E. of the body increases by $ K.E.=W=q( V _{A}-V _{B} ) $
$ ={{10}^{-8}}( 600-0 )=6\times {{10}^{-6}}J $
