Electrostatics Question 793

Question: A ball of mass 1 g carrying a change $ {{10}^{-8}}C $ moves from a point A at potential 600 V to a point B at zero potential. The change in its K.E.

Options:

A) $ -6\times {{10}^{-6}}erg $

B) $ -6\times {{10}^{-6}}J $

C) $ 6\times {{10}^{-6}}J $

D) $ 6\times {{10}^{-6}}erg $

Show Answer

Answer:

Correct Answer: C

Solution:

[c] As work is done by the field, K.E. of the body increases by $ K.E.=W=q( V _{A}-V _{B} ) $

$ ={{10}^{-8}}( 600-0 )=6\times {{10}^{-6}}J $



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