Electrostatics Question 772
Question: A conducting sphere of radius R is given a charge Q. The electric potential and the electric field at the center of the sphere respectively are:
Options:
A) $ 0\text{ and }\frac{Q}{4\pi \varepsilon { _{0}}R^{2}} $
B) $ \frac{Q}{4\pi \varepsilon { _{0}}R}\text{ and 0} $
C) $ \frac{Q}{4\pi \varepsilon { _{0}}R}\text{ and }\frac{Q}{4\pi \varepsilon { _{0}}R^{2}} $
D) Both are 0
Show Answer
Answer:
Correct Answer: B
Solution:
[b] Due to conducting sphere At center, electric field E=0 And electric potential
$ V=\frac{Q}{4\pi {\varepsilon _{0}}R} $
