Electrostatics Question 772

Question: A conducting sphere of radius R is given a charge Q. The electric potential and the electric field at the center of the sphere respectively are:

Options:

A) $ 0\text{ and }\frac{Q}{4\pi \varepsilon { _{0}}R^{2}} $

B) $ \frac{Q}{4\pi \varepsilon { _{0}}R}\text{ and 0} $

C) $ \frac{Q}{4\pi \varepsilon { _{0}}R}\text{ and }\frac{Q}{4\pi \varepsilon { _{0}}R^{2}} $

D) Both are 0

Show Answer

Answer:

Correct Answer: B

Solution:

[b] Due to conducting sphere At center, electric field E=0 And electric potential

$ V=\frac{Q}{4\pi {\varepsilon _{0}}R} $



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