SATHEE: Electrostatics Question 747

Electrostatics Question 747

Question: The magnitude of the average electric field normally present in the atmosphere just above the surface of the Earth is about 150 N/C, directed inward towards the center of the Earth. This gives the total net surface charge carried by the Earth to be: [Given $ε_{0} = 8.85 \times 10^{- 12} C^{2} / N - m^{2},$

$R_{E} =$

$6.37 \times 10^{6} m$ ] magnitude of the average electric field normally present in the atmosphere just above the surface of the Earth is about 150 N/C, directed inward

Options:

A) +670kC

B) -670kC

C) -680kC

D) +680kC

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Given, Electric field $E = 150 N / C$

Total surface charge carried by earth $q = ?$

According to Gauss’s law.

$ϕ = \frac{q}{ε_{0}} = E A$ or, $q = \in_{0} E A = \in_{0} E π r^{2} = 8.85 \times 10^{- 12} \times 150 \times$

${(6.37 \times 10^{6})}^{2} .$

As electric field directed inward hence $q = - 680 K C$

Electrostatics Question 747

Options:

Answer:

Solution:

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Electrostatics Question 747

Question: The magnitude of the average electric field normally present in the atmosphere just above the surface of the Earth is about 150 N/C, directed inward towards the center of the Earth. This gives the total net surface charge carried by the Earth to be: [Given ε0=8.85×10−12C2/N−m2,

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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