Electrostatics Question 747

Question: The magnitude of the average electric field normally present in the atmosphere just above the surface of the Earth is about 150 N/C, directed inward towards the center of the Earth. This gives the total net surface charge carried by the Earth to be: [Given $ {\varepsilon _{0}}=8.85\times {{10}^{-12}}C^{2}/N-m^{2}, $

$ R _{E}= $

$ 6.37\times 10^{6}m $ ] magnitude of the average electric field normally present in the atmosphere just above the surface of the Earth is about 150 N/C, directed inward

Options:

A) +670kC

B) -670kC

C) -680kC

D) +680kC

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Given, Electric field $ E=150N/C $

Total surface charge carried by earth $ q=? $

According to Gauss’s law.

$ \phi =\frac{q}{{\varepsilon _{0}}}=EA $ or, $ q={\in _{0}}EA={\in _{0}}E\pi r^{2}=8.85\times {{10}^{-12}}\times 150\times $

$ {{(6.37\times 10^{6})}^{2}}. $

As electric field directed inward hence $ q=-680KC $



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