Electrostatics Question 745

Question: The surface density on the copper sphere is $ \sigma . $ The electric field strength on the surface of the sphere is

Options:

A) $ \sigma $

B) $ \sigma /2 $

C) $ \sigma /2{\varepsilon _{0}} $

D) $ Q/{\varepsilon _{0}} $

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Answer:

Correct Answer: D

Solution:

[d] According to Gauss’s theorem, $ E\int _{ds=\frac{q}{{\in _{0}}}[ \text{Here}\int _{ds}=4\pi R^{2} ]} $

$ \therefore E=\frac{q/4\pi R^{2}}{{\in _{0}}}[ \therefore q/4\pi R^{2}=\sigma ] $ or $ E=\sigma /{\in _{0}} $



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