Electrostatics Question 745
Question: The surface density on the copper sphere is $ \sigma . $ The electric field strength on the surface of the sphere is
Options:
A) $ \sigma $
B) $ \sigma /2 $
C) $ \sigma /2{\varepsilon _{0}} $
D) $ Q/{\varepsilon _{0}} $
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Answer:
Correct Answer: D
Solution:
[d] According to Gauss’s theorem, $ E\int _{ds=\frac{q}{{\in _{0}}}[ \text{Here}\int _{ds}=4\pi R^{2} ]} $
$ \therefore E=\frac{q/4\pi R^{2}}{{\in _{0}}}[ \therefore q/4\pi R^{2}=\sigma ] $ or $ E=\sigma /{\in _{0}} $
