Electrostatics Question 742
Question: A surface has the area vector $ \vec{A}=( 2\hat{i}+3\hat{j} )m^{2}. $ The flux of an electric field through it if the field is $ \vec{E}=4\hat{i}\frac{V}{m}: $
Options:
A) 8V-m
B) 12Vm
C) 20V-m
D) zero
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ \phi =\vec{E}.\vec{A}=4\hat{i}.( 2\hat{i}+3\hat{j} )=8V-m $
