Electrostatics Question 742

Question: A surface has the area vector $ \vec{A}=( 2\hat{i}+3\hat{j} )m^{2}. $ The flux of an electric field through it if the field is $ \vec{E}=4\hat{i}\frac{V}{m}: $

Options:

A) 8V-m

B) 12Vm

C) 20V-m

D) zero

Show Answer

Answer:

Correct Answer: A

Solution:

[a] $ \phi =\vec{E}.\vec{A}=4\hat{i}.( 2\hat{i}+3\hat{j} )=8V-m $



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