Electrostatics Question 727

Question: The total electric flux emanating from a closed surface enclosing an $ \alpha - $ particle is (e-electronic charge)

Options:

A) $ \frac{2e}{{\varepsilon _{0}}} $

B) $ \frac{e}{{\varepsilon _{0}}} $

C) $ e{\varepsilon _{0}} $

D) $ \frac{{\varepsilon _{0}}e}{4} $

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Answer:

Correct Answer: A

Solution:

[a] According to Gauss’s law total electric flux through a closed surface is $ \frac{1}{{\varepsilon _{0}}} $ times the total charge inside that surface.

Electric flux, $ {\phi _{E}}=\frac{q}{{\varepsilon _{0}}} $

Charge on $ \alpha - $ particle=2e $ \therefore {\phi _{E}}=\frac{2e}{{\varepsilon _{0}}} $



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