Electrostatics Question 727
Question: The total electric flux emanating from a closed surface enclosing an $ \alpha - $ particle is (e-electronic charge)
Options:
A) $ \frac{2e}{{\varepsilon _{0}}} $
B) $ \frac{e}{{\varepsilon _{0}}} $
C) $ e{\varepsilon _{0}} $
D) $ \frac{{\varepsilon _{0}}e}{4} $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] According to Gauss’s law total electric flux through a closed surface is $ \frac{1}{{\varepsilon _{0}}} $ times the total charge inside that surface.
Electric flux, $ {\phi _{E}}=\frac{q}{{\varepsilon _{0}}} $
Charge on $ \alpha - $ particle=2e $ \therefore {\phi _{E}}=\frac{2e}{{\varepsilon _{0}}} $
