Electrostatics Question 633
Question: Three capacitors of capacitance 1 mF, 2 mF and 3 mF are connected in series and a potential difference of 11 V is applied across the combination. Then, the potential difference across the plates of 1 mF capacitor is [DCE 2003]
Options:
A) 2 V
B) 4 V
C) 1 V
D) 6 V
Show Answer
Answer:
Correct Answer: D
Solution:
Equivalent capacitance $ \frac{1}{C _{eq}}=\frac{1}{1}+\frac{1}{2}+\frac{1}{3} $
therefore $ C _{eq}=\frac{6}{11}\mu F $
Charge supplied from battery $ Q=\frac{6}{11}\times 11=6\mu C $
Hence potential difference across 1mF capacitor $ =\frac{6}{1}=6V $
