Electrostatics Question 633

Question: Three capacitors of capacitance 1 mF, 2 mF and 3 mF are connected in series and a potential difference of 11 V is applied across the combination. Then, the potential difference across the plates of 1 mF capacitor is [DCE 2003]

Options:

A) 2 V

B) 4 V

C) 1 V

D) 6 V

Show Answer

Answer:

Correct Answer: D

Solution:

Equivalent capacitance $ \frac{1}{C _{eq}}=\frac{1}{1}+\frac{1}{2}+\frac{1}{3} $

therefore $ C _{eq}=\frac{6}{11}\mu F $

Charge supplied from battery $ Q=\frac{6}{11}\times 11=6\mu C $

Hence potential difference across 1mF capacitor $ =\frac{6}{1}=6V $



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