Electrostatics Question 613

Question: Two capacitors of capacitances 3μF and 6μF are charged to a potential of 12 V each. They are now connected to each other, with the positive plate of each joined to the negative plate of the other. The potential difference across each will be [KCET 2002]

Options:

A) 6 volt

B) 4 volt

C) 3 volt

D) Zero

Show Answer

Answer:

Correct Answer: B

Solution:

V=C1V1−C2V2C1+C2=6×12−3×123+6=4volt

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