Electrostatics Question 613

Question: Two capacitors of capacitances $ 3\mu F $ and $ 6\mu F $ are charged to a potential of 12 V each. They are now connected to each other, with the positive plate of each joined to the negative plate of the other. The potential difference across each will be [KCET 2002]

Options:

A) 6 volt

B) 4 volt

C) 3 volt

D) Zero

Show Answer

Answer:

Correct Answer: B

Solution:

$ V=\frac{C _{1}V _{1}-C _{2}V _{2}}{C _{1}+C _{2}}=\frac{6\times 12-3\times 12}{3+6}=4volt $



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